T > wrote:
>In article >, says...
>> R = ((130 - T)/(T - 70)) * (14400 / W)
>> where W is the actual wattage of the unit (which is probably a value
>> somewhat lower than its rated wattage), 130 is the observed
>> temperature now, 70 is the ambient temperature, T is the desired
>> temperature, and 14400 is the square of the line voltage.
>If I may, R = ((130-T)/(T-70)) *(V^2 / W) since 120V isn't normal in
>some places.
>
>For example for me I'd have to do R = ((130-T)/(T-70)) * (125^2 / W)
>
>I've measured it, and it's definitely 125V service where I live.
Of course. Neither is 70 degrees the ambient temperature
everywhere.
But the biggest unknown is the value of W, if you don't have
a multimeter. Hence my use of the term "guestimate".
Steve