Leo Bueno > wrote:
>
> Because it is not easy to measure the temperature INSIDE the bottle.
>
> Given that "room temperature" is generally uniform in the
> climate-controlled world and so are refrigerator temperatures, a
> refrigeration time rule of thumb may not be bad approximation.
ok, in that case, take a time constant of 20 mn (saying tau), as a rule
of thumb, then, having T1 the romm temperature where the bottle was,
take T2 the fridge temperature, the bottle temperature will follow :
Tbottle = T1 + (T2 - T1).e^( - time / tau)
time being expressed in the same unit as tau...
for time in hours (tau = 1/3) gives :
Tbottle = T1 + (T2 - T1).e^( - 3.time)
giving, for time :
time (in hours) = (ln((T2 - T1)/(Tbottle - T1)))/3
as far as i remember well algebraic computation ;-)
--
Yvon Thoraval
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